From Frederick.Gray@pomona.edu Mon Oct 9 21:06:20 2006 Hi, Peter, In the heat of the moment yesterday, it seems that I forgot to remove my own secret offset! Our agreement with the PDG turns out to be perfect. I begin with the result from p. 28 of my analysis report: lambda = 454.755 ± 0.0249 (stat.) ± 0.0131(syst.) kHz My secret "offset" was multiplication by (1 + delta). In my report, I identified delta as ~O(10^-4). In fact, delta = 10^-4 precisely: there were a lot of not-very-creative offsets used in this experiment. Therefore, when I remove my offset by dividing by 1.0001, leaving only the blinded clock frequency, I obtain lambda = 454.709 ± 0.0249 (stat.) ± 0.0131(syst.) kHz When I also remove the clock blinding by multiplying by (100.1/100), then I obtain lambda = 455.164 ± 0.0249 (stat.) ± 0.0131(syst.) kHz The PDG value for the muon lifetime is 2.19703 ± 0.00004 microseconds, corresponding to 455.1599 ± 0.0083 kHz decay rate. Therefore, the difference between our result and the PDG is 0.004 ± 0.029 kHz, or 0.14 sigma. -- Fred ---------------------------------------------------------------------- Frederick Gray, Visiting Assistant Professor Department of Physics and Astronomy, Pomona College, Claremont, CA, USA Frederick.Gray@pomona.edu / phone: 909-607-9795 / fax: 909-621-8463 ---------------------------------------------------------------------- On Oct 9, 2006, at 3:31 PM, Peter Kammel wrote: > Dear Fred, > > Could you send me a few lines about the mu+ lifetime > unblind (your secret offset) and I will include > this in the results spreadsheet, which I will > send to the collaboration tomorrow. > > Thanks > > Peter > ------------------------------------------------------------- This message has been scanned by Postini anti-virus software.